Thursday, December 13, 2012

Habitat for Humanity House Project

Description
The affordable housing project I designed is a Habitat for Humanity house located in Noblesville, IN. A map of the area is provided below. This house was designed for the Woodward family, a family of two. There is one adult and one child sharing a two bedroom home. Incorporated into the house are the following sustainable design features: Feasible daylighting and Energy Star rated appliances. Being constrained to the Habitat for Humanity guidelines, I had to keep the house within 900 square feet. To give the relatively small home an open and, thus, larger feeling, I arranged all of the home's rooms around an open living room/kitchen/dining room area that was separated with a small partician to save space, provide an open, flowing atmosphere, with some privacy to those in the kitchen and dining area. The client originally wanted an attached porch, but after incorporating it into the design, it put the total area over the limit. Removing it, however, put the area somewhat under the limit so I enlarged the size of the bathroom. We agreed that this was an acceptable compramize.



Bubble Diagram and Rough Sketch


Renderings


Site Plan


Dimensioned Floor Plan



Elevations (all 4)


Wall Sections with Lables


Window and Door Schedule


Room Schedule with Total Sq. Footage



Electrical Plan


Plumbing Plan




Calculations

Water Pressure Calculations
LengthL=16565.3ft
Flow RateQ=100gpm
Hazzen-Williams CoefficientC=100
Diameterd=8in
Static Head=109.81ft
Head LossHf=7ft
Dynamic Head=102.83ft
Actual Pressure=44.51psi


Part 1: Calculation of site runoff prior to addition of parking lotPre-development
Pre-development  (for 100 year storm)
Q = CfCiA
C = 0.1
i = 3.05
A = 0.5 acres (from site plan)
Q= (1.25)(0.1)(3.05)(0.5) = 0.2 cfs

Post-development (for 100 year storm)
Q = CfCiA
C (grass) = 0.1
C (asphalt) = .95
C (roof) = .95
i = 3.05
A (grass) = 0.47 acres
A (roof) = 0.02 acres 
A (drive way) = 0.01 acres
Q = [(1.05)(0.1)(3.05)(0.47)] + [(1.05)(0.95)(3.05)(0.02)] + [(1.05)(0.95)(3.05)(0.01)]
Q = 0.15 + 0.06 + 0.03
Q = 0.24
Change in runoff
ΔQ = Qpost - Qpre 
ΔQ = 0.24 - 0.2
ΔQ = 0.04
The change in runoff of the post development site is .04. Digging a small ditch will provide proper space for the water to go.